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	<title>Comments on: Two fire look out stations are 20 miles apart with station B east of station A. Both station spot a fire?</title>
	<atom:link href="http://www.wegafire.com/fire-station/two-fire-look-out-stations-are-20-miles-apart-with-station-b-east-of-station-a-both-station-spot-a-fire/feed" rel="self" type="application/rss+xml" />
	<link>http://www.wegafire.com/fire-station/two-fire-look-out-stations-are-20-miles-apart-with-station-b-east-of-station-a-both-station-spot-a-fire</link>
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		<title>By: Kim</title>
		<link>http://www.wegafire.com/fire-station/two-fire-look-out-stations-are-20-miles-apart-with-station-b-east-of-station-a-both-station-spot-a-fire/comment-page-1#comment-2070</link>
		<dc:creator>Kim</dc:creator>
		<pubDate>Tue, 02 Mar 2010 14:28:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.wegafire.com/fire-station/two-fire-look-out-stations-are-20-miles-apart-with-station-b-east-of-station-a-both-station-spot-a-fire#comment-2070</guid>
		<description>N 60° E means &quot;60° east of north&quot;
N 40° W means &quot;40° west of north&quot;

It helps if you draw a triangle.

If you draw vertical lines on either side of the triangle, you can see that the exterior angle of A is 60 degrees, so the inner angle must be 30.

The exterior angle of angle B is 40, so the inner angle is 50 degrees.

All the interior angles add up to 180 degrees, so angle C is 100 degrees.

A = 30 degrees
B= 50 degrees
C = 100 degrees
a = ?
b = ?
c = 20 miles

 Now you can use the Rule of Sines to solve the rest.

a/sinA = b/sinB = c/sinC

b/sinB = 20/sin100

b = (20sin50)/sin100

b is about 15.57 miles

Using the same rule, a was about 10.2 miles.

Anyway the answer was 15.57 miles rounded up to 16.&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>N 60° E means &quot;60° east of north&quot;<br />
N 40° W means &quot;40° west of north&quot;</p>
<p>It helps if you draw a triangle.</p>
<p>If you draw vertical lines on either side of the triangle, you can see that the exterior angle of A is 60 degrees, so the inner angle must be 30.</p>
<p>The exterior angle of angle B is 40, so the inner angle is 50 degrees.</p>
<p>All the interior angles add up to 180 degrees, so angle C is 100 degrees.</p>
<p>A = 30 degrees<br />
B= 50 degrees<br />
C = 100 degrees<br />
a = ?<br />
b = ?<br />
c = 20 miles</p>
<p> Now you can use the Rule of Sines to solve the rest.</p>
<p>a/sinA = b/sinB = c/sinC</p>
<p>b/sinB = 20/sin100</p>
<p>b = (20sin50)/sin100</p>
<p>b is about 15.57 miles</p>
<p>Using the same rule, a was about 10.2 miles.</p>
<p>Anyway the answer was 15.57 miles rounded up to 16.<br /><b>References : </b></p>
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	<item>
		<title>By: Dilon</title>
		<link>http://www.wegafire.com/fire-station/two-fire-look-out-stations-are-20-miles-apart-with-station-b-east-of-station-a-both-station-spot-a-fire/comment-page-1#comment-2069</link>
		<dc:creator>Dilon</dc:creator>
		<pubDate>Tue, 02 Mar 2010 14:12:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.wegafire.com/fire-station/two-fire-look-out-stations-are-20-miles-apart-with-station-b-east-of-station-a-both-station-spot-a-fire#comment-2069</guid>
		<description>15.6 m&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>15.6 m<br /><b>References : </b></p>
]]></content:encoded>
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	<item>
		<title>By: Rik D</title>
		<link>http://www.wegafire.com/fire-station/two-fire-look-out-stations-are-20-miles-apart-with-station-b-east-of-station-a-both-station-spot-a-fire/comment-page-1#comment-2068</link>
		<dc:creator>Rik D</dc:creator>
		<pubDate>Tue, 02 Mar 2010 13:46:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.wegafire.com/fire-station/two-fire-look-out-stations-are-20-miles-apart-with-station-b-east-of-station-a-both-station-spot-a-fire#comment-2068</guid>
		<description>N 60° E means &quot;60° east of north&quot;
N 40° W means &quot;40° west of north&quot;

d = sqrt(  f^2 + h^2  )

tan 30° = h/f =&gt;

f = h / tan 30°

tan 50° = h / g =&gt;

g = h / tan 50°

f + g = [h / tan 30°] + [h / tan 50°] = 20 =&gt;

(1 / tan 30°  +  1 / tan 50° )h = 20 =&gt;

h = 20 / (1 / tan 30°  +  1 / tan 50° )
  
   = 7.77861913 mi =&gt;

f = 7.77861913 / tan 30°

  = 13.4729635 mi =&gt;

d = sqrt(  13.4729635^2  +  7.77861913^2  )

   = 15.5572382 mi

   ˜ 15.6 mi&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;Googled it</description>
		<content:encoded><![CDATA[<p>N 60° E means &quot;60° east of north&quot;<br />
N 40° W means &quot;40° west of north&quot;</p>
<p>d = sqrt(  f^2 + h^2  )</p>
<p>tan 30° = h/f =&gt;</p>
<p>f = h / tan 30°</p>
<p>tan 50° = h / g =&gt;</p>
<p>g = h / tan 50°</p>
<p>f + g = [h / tan 30°] + [h / tan 50°] = 20 =&gt;</p>
<p>(1 / tan 30°  +  1 / tan 50° )h = 20 =&gt;</p>
<p>h = 20 / (1 / tan 30°  +  1 / tan 50° )</p>
<p>   = 7.77861913 mi =&gt;</p>
<p>f = 7.77861913 / tan 30°</p>
<p>  = 13.4729635 mi =&gt;</p>
<p>d = sqrt(  13.4729635^2  +  7.77861913^2  )</p>
<p>   = 15.5572382 mi</p>
<p>   ˜ 15.6 mi<br /><b>References : </b><br />Googled it</p>
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